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4340242553443 is a prime number
BaseRepresentation
bin111111001010001010100…
…111011001101001100011
3120100220220222002020221121
4333022022213121221203
51032102304043202233
613121514020433111
7625400153665246
oct77121247315143
916326828066847
104340242553443
1114237608539a5
125a1202548797
1325638b012a34
141100d6d4b25d
1577d765b392d
hex3f28a9d9a63

4340242553443 has 2 divisors, whose sum is σ = 4340242553444. Its totient is φ = 4340242553442.

The previous prime is 4340242553399. The next prime is 4340242553461. The reversal of 4340242553443 is 3443552420434.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4340242553443 - 29 = 4340242552931 is a prime.

It is a super-2 number, since 2×43402425534432 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4340242553443.

It is not a weakly prime, because it can be changed into another prime (4340242593443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170121276721 + 2170121276722.

It is an arithmetic number, because the mean of its divisors is an integer number (2170121276722).

Almost surely, 24340242553443 is an apocalyptic number.

4340242553443 is a deficient number, since it is larger than the sum of its proper divisors (1).

4340242553443 is an equidigital number, since it uses as much as digits as its factorization.

4340242553443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2764800, while the sum is 43.

Adding to 4340242553443 its reverse (3443552420434), we get a palindrome (7783794973877).

The spelling of 4340242553443 in words is "four trillion, three hundred forty billion, two hundred forty-two million, five hundred fifty-three thousand, four hundred forty-three".