Base | Representation |
---|---|
bin | 111111001010001010100… |
… | …111011001101001101011 |
3 | 120100220220222002020221220 |
4 | 333022022213121221223 |
5 | 1032102304043202301 |
6 | 13121514020433123 |
7 | 625400153665260 |
oct | 77121247315153 |
9 | 16326828066856 |
10 | 4340242553451 |
11 | 1423760853a02 |
12 | 5a12025487a3 |
13 | 25638b012a3c |
14 | 1100d6d4b267 |
15 | 77d765b3936 |
hex | 3f28a9d9a6b |
4340242553451 has 8 divisors (see below), whose sum is σ = 6613702938624. Its totient is φ = 2480138601960.
The previous prime is 4340242553443. The next prime is 4340242553461. The reversal of 4340242553451 is 1543552420434.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4340242553451 - 23 = 4340242553443 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4340242553461) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 103339108395 + ... + 103339108436.
It is an arithmetic number, because the mean of its divisors is an integer number (826712867328).
Almost surely, 24340242553451 is an apocalyptic number.
4340242553451 is a deficient number, since it is larger than the sum of its proper divisors (2273460385173).
4340242553451 is a wasteful number, since it uses less digits than its factorization.
4340242553451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206678216841.
The product of its (nonzero) digits is 1152000, while the sum is 42.
Adding to 4340242553451 its reverse (1543552420434), we get a palindrome (5883794973885).
The spelling of 4340242553451 in words is "four trillion, three hundred forty billion, two hundred forty-two million, five hundred fifty-three thousand, four hundred fifty-one".
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