Base | Representation |
---|---|
bin | 1100101000011011101… |
… | …11101101000010111101 |
3 | 1112111021220111010121211 |
4 | 12110031313231002331 |
5 | 24102340221400013 |
6 | 531215453124421 |
7 | 43233346361416 |
oct | 6241567550275 |
9 | 1474256433554 |
10 | 434024403133 |
11 | 158083508032 |
12 | 70149a89711 |
13 | 31c0b6ba469 |
14 | 17014cb480d |
15 | b4539b823d |
hex | 650dded0bd |
434024403133 has 2 divisors, whose sum is σ = 434024403134. Its totient is φ = 434024403132.
The previous prime is 434024403121. The next prime is 434024403157. The reversal of 434024403133 is 331304420434.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 331340686884 + 102683716249 = 575622^2 + 320443^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-434024403133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 434024403095 and 434024403104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434024403433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217012201566 + 217012201567.
It is an arithmetic number, because the mean of its divisors is an integer number (217012201567).
Almost surely, 2434024403133 is an apocalyptic number.
It is an amenable number.
434024403133 is a deficient number, since it is larger than the sum of its proper divisors (1).
434024403133 is an equidigital number, since it uses as much as digits as its factorization.
434024403133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 434024403133 its reverse (331304420434), we get a palindrome (765328823567).
The spelling of 434024403133 in words is "four hundred thirty-four billion, twenty-four million, four hundred three thousand, one hundred thirty-three".
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