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434024403133 is a prime number
BaseRepresentation
bin1100101000011011101…
…11101101000010111101
31112111021220111010121211
412110031313231002331
524102340221400013
6531215453124421
743233346361416
oct6241567550275
91474256433554
10434024403133
11158083508032
1270149a89711
1331c0b6ba469
1417014cb480d
15b4539b823d
hex650dded0bd

434024403133 has 2 divisors, whose sum is σ = 434024403134. Its totient is φ = 434024403132.

The previous prime is 434024403121. The next prime is 434024403157. The reversal of 434024403133 is 331304420434.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 331340686884 + 102683716249 = 575622^2 + 320443^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-434024403133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 434024403095 and 434024403104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (434024403433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217012201566 + 217012201567.

It is an arithmetic number, because the mean of its divisors is an integer number (217012201567).

Almost surely, 2434024403133 is an apocalyptic number.

It is an amenable number.

434024403133 is a deficient number, since it is larger than the sum of its proper divisors (1).

434024403133 is an equidigital number, since it uses as much as digits as its factorization.

434024403133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 434024403133 its reverse (331304420434), we get a palindrome (765328823567).

The spelling of 434024403133 in words is "four hundred thirty-four billion, twenty-four million, four hundred three thousand, one hundred thirty-three".