Base | Representation |
---|---|
bin | 111111001010001010110… |
… | …001111101111100001101 |
3 | 120100220221011021222210112 |
4 | 333022022301331330031 |
5 | 1032102310300323113 |
6 | 13121514200045405 |
7 | 625400216353310 |
oct | 77121261757415 |
9 | 16326834258715 |
10 | 4340245323533 |
11 | 1423762376129 |
12 | 5a1203463865 |
13 | 25638b772842 |
14 | 1100d746c977 |
15 | 77d7695e5a8 |
hex | 3f28ac7df0d |
4340245323533 has 4 divisors (see below), whose sum is σ = 4960280369760. Its totient is φ = 3720210277308.
The previous prime is 4340245323523. The next prime is 4340245323539. The reversal of 4340245323533 is 3353235420434.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 4340245323533 - 210 = 4340245322509 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4340245323539) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 310017523103 + ... + 310017523116.
It is an arithmetic number, because the mean of its divisors is an integer number (1240070092440).
Almost surely, 24340245323533 is an apocalyptic number.
It is an amenable number.
4340245323533 is a deficient number, since it is larger than the sum of its proper divisors (620035046227).
4340245323533 is an equidigital number, since it uses as much as digits as its factorization.
4340245323533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 620035046226.
The product of its (nonzero) digits is 1555200, while the sum is 41.
The spelling of 4340245323533 in words is "four trillion, three hundred forty billion, two hundred forty-five million, three hundred twenty-three thousand, five hundred thirty-three".
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