43403200141 has 4 divisors (see below), whose sum is σ = 49603657312. Its totient is φ = 37202742972.

The previous prime is 43403200133. The next prime is 43403200153. The reversal of 43403200141 is 14100230434.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14100230434 = 2 ⋅7050115217.

It is a cyclic number.

It is not a de Polignac number, because 43403200141 - 2³ = 43403200133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43403210141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3100228575 + ... + 3100228588.

It is an arithmetic number, because the mean of its divisors is an integer number (12400914328).

Almost surely, 2^43403200141 is an apocalyptic number.

It is an amenable number.

43403200141 is a deficient number, since it is larger than the sum of its proper divisors (6200457171).

43403200141 is an equidigital number, since it uses as much as digits as its factorization.

43403200141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6200457170.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 43403200141 its reverse (14100230434), we get a palindrome (57503430575).

The spelling of 43403200141 in words is "forty-three billion, four hundred three million, two hundred thousand, one hundred forty-one".