Base | Representation |
---|---|
bin | 111111001010010100000… |
… | …011111010000011001100 |
3 | 120100221100000021020202021 |
4 | 333022110003322003030 |
5 | 1032103120130134012 |
6 | 13121541441135524 |
7 | 625404116643211 |
oct | 77122403720314 |
9 | 16327300236667 |
10 | 4340401021132 |
11 | 142383224a030 |
12 | 5a124762a5a4 |
13 | 2563b4ab7bb7 |
14 | 11010dddbb08 |
15 | 77d85467007 |
hex | 3f2940fa0cc |
4340401021132 has 12 divisors (see below), whose sum is σ = 8286220131336. Its totient is φ = 1972909555040.
The previous prime is 4340401021129. The next prime is 4340401021139. The reversal of 4340401021132 is 2311201040434.
It is a super-2 number, since 2×43404010211322 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4340401021097 and 4340401021106.
It is not an unprimeable number, because it can be changed into a prime (4340401021139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49322738833 + ... + 49322738920.
It is an arithmetic number, because the mean of its divisors is an integer number (690518344278).
Almost surely, 24340401021132 is an apocalyptic number.
It is an amenable number.
4340401021132 is a deficient number, since it is larger than the sum of its proper divisors (3945819110204).
4340401021132 is a wasteful number, since it uses less digits than its factorization.
4340401021132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98645477768 (or 98645477766 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4340401021132 its reverse (2311201040434), we get a palindrome (6651602061566).
The spelling of 4340401021132 in words is "four trillion, three hundred forty billion, four hundred one million, twenty-one thousand, one hundred thirty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •