Base | Representation |
---|---|
bin | 111111001010111010111… |
… | …011111110011000010111 |
3 | 120101000000110120001212102 |
4 | 333022322323332120113 |
5 | 1032110434113100033 |
6 | 13122130300512315 |
7 | 625426226554235 |
oct | 77127273763027 |
9 | 16330013501772 |
10 | 4341053253143 |
11 | 1424037432652 |
12 | 5a13a9b4b69b |
13 | 256489c70ab9 |
14 | 11017289d955 |
15 | 77dc2850de8 |
hex | 3f2baefe617 |
4341053253143 has 2 divisors, whose sum is σ = 4341053253144. Its totient is φ = 4341053253142.
The previous prime is 4341053253127. The next prime is 4341053253227. The reversal of 4341053253143 is 3413523501434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4341053253143 - 24 = 4341053253127 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4341053253097 and 4341053253106.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4341053253343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170526626571 + 2170526626572.
It is an arithmetic number, because the mean of its divisors is an integer number (2170526626572).
Almost surely, 24341053253143 is an apocalyptic number.
4341053253143 is a deficient number, since it is larger than the sum of its proper divisors (1).
4341053253143 is an equidigital number, since it uses as much as digits as its factorization.
4341053253143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 4341053253143 its reverse (3413523501434), we get a palindrome (7754576754577).
The spelling of 4341053253143 in words is "four trillion, three hundred forty-one billion, fifty-three million, two hundred fifty-three thousand, one hundred forty-three".
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