Base | Representation |
---|---|
bin | 111111001011000100100… |
… | …001101000110111011010 |
3 | 120101000102200021000200021 |
4 | 333023010201220313122 |
5 | 1032111301303341214 |
6 | 13122154244501054 |
7 | 625433222121061 |
oct | 77130441506732 |
9 | 16330380230607 |
10 | 4341214121434 |
11 | 142410a218353 |
12 | 5a14339aa78a |
13 | 2564b43a6838 |
14 | 110189db71d8 |
15 | 77dd1a2a924 |
hex | 3f2c4868dda |
4341214121434 has 16 divisors (see below), whose sum is σ = 6576745592736. Its totient is φ = 2148968538000.
The previous prime is 4341214121423. The next prime is 4341214121443.
4341214121434 is nontrivially palindromic in base 10.
It is a super-3 number, since 3×43412141214343 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an alternating number because its digits alternate between even and odd.
It is a self number, because there is not a number n which added to its sum of digits gives 4341214121434.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2246209 + ... + 3705115.
It is an arithmetic number, because the mean of its divisors is an integer number (411046599546).
Almost surely, 24341214121434 is an apocalyptic number.
4341214121434 is a deficient number, since it is larger than the sum of its proper divisors (2235531471302).
4341214121434 is a wasteful number, since it uses less digits than its factorization.
4341214121434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1473741.
The product of its digits is 36864, while the sum is 34.
The spelling of 4341214121434 in words is "four trillion, three hundred forty-one billion, two hundred fourteen million, one hundred twenty-one thousand, four hundred thirty-four".
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