Base | Representation |
---|---|
bin | 1100101000100111011… |
… | …00011101101110111001 |
3 | 1112111112201100200010112 |
4 | 12110103230131232321 |
5 | 24103040230320441 |
6 | 531233303354105 |
7 | 43235644064534 |
oct | 6242354355671 |
9 | 1474481320115 |
10 | 434122120121 |
11 | 15812368a278 |
12 | 70176752935 |
13 | 31c25a11a71 |
14 | 17023c6da1b |
15 | b45c36b4eb |
hex | 6513b1dbb9 |
434122120121 has 2 divisors, whose sum is σ = 434122120122. Its totient is φ = 434122120120.
The previous prime is 434122120109. The next prime is 434122120163. The reversal of 434122120121 is 121021221434.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 381385294096 + 52736826025 = 617564^2 + 229645^2 .
It is a cyclic number.
It is not a de Polignac number, because 434122120121 - 230 = 433048378297 is a prime.
It is not a weakly prime, because it can be changed into another prime (434122120171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217061060060 + 217061060061.
It is an arithmetic number, because the mean of its divisors is an integer number (217061060061).
Almost surely, 2434122120121 is an apocalyptic number.
It is an amenable number.
434122120121 is a deficient number, since it is larger than the sum of its proper divisors (1).
434122120121 is an equidigital number, since it uses as much as digits as its factorization.
434122120121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 434122120121 its reverse (121021221434), we get a palindrome (555143341555).
The spelling of 434122120121 in words is "four hundred thirty-four billion, one hundred twenty-two million, one hundred twenty thousand, one hundred twenty-one".
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