Base | Representation |
---|---|
bin | 1100101000100111100… |
… | …11101000101110011101 |
3 | 1112111112211220012001111 |
4 | 12110103303220232131 |
5 | 24103041221001112 |
6 | 531233411542021 |
7 | 43235666054641 |
oct | 6242363505635 |
9 | 1474484805044 |
10 | 434124000157 |
11 | 158124753821 |
12 | 701772ba911 |
13 | 31c2621c703 |
14 | 170241dcc21 |
15 | b45c5dd5a7 |
hex | 6513ce8b9d |
434124000157 has 2 divisors, whose sum is σ = 434124000158. Its totient is φ = 434124000156.
The previous prime is 434124000119. The next prime is 434124000173. The reversal of 434124000157 is 751000421434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 282876123321 + 151247876836 = 531861^2 + 388906^2 .
It is a cyclic number.
It is not a de Polignac number, because 434124000157 - 219 = 434123475869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434124000757) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217062000078 + 217062000079.
It is an arithmetic number, because the mean of its divisors is an integer number (217062000079).
Almost surely, 2434124000157 is an apocalyptic number.
It is an amenable number.
434124000157 is a deficient number, since it is larger than the sum of its proper divisors (1).
434124000157 is an equidigital number, since it uses as much as digits as its factorization.
434124000157 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 31.
The spelling of 434124000157 in words is "four hundred thirty-four billion, one hundred twenty-four million, one hundred fifty-seven", and thus it is an aban number.
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