Base | Representation |
---|---|
bin | 1100101000100111100… |
… | …11101000101111110001 |
3 | 1112111112211220012011121 |
4 | 12110103303220233301 |
5 | 24103041221001431 |
6 | 531233411542241 |
7 | 43235666055121 |
oct | 6242363505761 |
9 | 1474484805147 |
10 | 434124000241 |
11 | 158124753898 |
12 | 701772ba981 |
13 | 31c2621c769 |
14 | 170241dcc81 |
15 | b45c5dd611 |
hex | 6513ce8bf1 |
434124000241 has 4 divisors (see below), whose sum is σ = 434200315300. Its totient is φ = 434047685184.
The previous prime is 434124000239. The next prime is 434124000253. The reversal of 434124000241 is 142000421434.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 417579609616 + 16544390625 = 646204^2 + 128625^2 .
It is a cyclic number.
It is not a de Polignac number, because 434124000241 - 21 = 434124000239 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (434124007241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38148996 + ... + 38160373.
It is an arithmetic number, because the mean of its divisors is an integer number (108550078825).
Almost surely, 2434124000241 is an apocalyptic number.
It is an amenable number.
434124000241 is a deficient number, since it is larger than the sum of its proper divisors (76315059).
434124000241 is an equidigital number, since it uses as much as digits as its factorization.
434124000241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76315058.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 434124000241 its reverse (142000421434), we get a palindrome (576124421675).
The spelling of 434124000241 in words is "four hundred thirty-four billion, one hundred twenty-four million, two hundred forty-one", and thus it is an aban number.
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