Base | Representation |
---|---|
bin | 1100101000101000010… |
… | …10101001110101010111 |
3 | 1112111120021020201221102 |
4 | 12110110022221311113 |
5 | 24103044242042012 |
6 | 531234145140315 |
7 | 43236101255225 |
oct | 6242412516527 |
9 | 1474507221842 |
10 | 434130034007 |
11 | 1581280a507a |
12 | 7017932a69b |
13 | 31c27552c37 |
14 | 17024d2db15 |
15 | b45cdd12c2 |
hex | 65142a9d57 |
434130034007 has 2 divisors, whose sum is σ = 434130034008. Its totient is φ = 434130034006.
The previous prime is 434130033977. The next prime is 434130034027. The reversal of 434130034007 is 700430031434.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 434130034007 - 214 = 434130017623 is a prime.
It is a super-3 number, since 3×4341300340073 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434130034027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217065017003 + 217065017004.
It is an arithmetic number, because the mean of its divisors is an integer number (217065017004).
Almost surely, 2434130034007 is an apocalyptic number.
434130034007 is a deficient number, since it is larger than the sum of its proper divisors (1).
434130034007 is an equidigital number, since it uses as much as digits as its factorization.
434130034007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 29.
The spelling of 434130034007 in words is "four hundred thirty-four billion, one hundred thirty million, thirty-four thousand, seven".
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