4341321114541 has 2 divisors, whose sum is σ = 4341321114542. Its totient is φ = 4341321114540.

The previous prime is 4341321114461. The next prime is 4341321114553. The reversal of 4341321114541 is 1454111231434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4337935038441 + 3386076100 = 2082771^2 + 58190^2 .

It is a cyclic number.

It is not a de Polignac number, because 4341321114541 - 2¹⁹ = 4341320590253 is a prime.

It is a super-4 number, since 4×4341321114541⁴ (a number of 52 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4341321114497 and 4341321114506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4341321414541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170660557270 + 2170660557271.

It is an arithmetic number, because the mean of its divisors is an integer number (2170660557271).

Almost surely, 2^{4341321114541} is an apocalyptic number.

It is an amenable number.

4341321114541 is a deficient number, since it is larger than the sum of its proper divisors (1).

4341321114541 is an equidigital number, since it uses as much as digits as its factorization.

4341321114541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 23040, while the sum is 34.

Adding to 4341321114541 its reverse (1454111231434), we get a palindrome (5795432345975).

The spelling of 4341321114541 in words is "four trillion, three hundred forty-one billion, three hundred twenty-one million, one hundred fourteen thousand, five hundred forty-one".