4341325512143 has 2 divisors, whose sum is σ = 4341325512144. Its totient is φ = 4341325512142.

The previous prime is 4341325512079. The next prime is 4341325512163. The reversal of 4341325512143 is 3412155231434.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4341325512143 - 2⁶ = 4341325512079 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4341325512097 and 4341325512106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4341325512163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170662756071 + 2170662756072.

It is an arithmetic number, because the mean of its divisors is an integer number (2170662756072).

Almost surely, 2^{4341325512143} is an apocalyptic number.

4341325512143 is a deficient number, since it is larger than the sum of its proper divisors (1).

4341325512143 is an equidigital number, since it uses as much as digits as its factorization.

4341325512143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 172800, while the sum is 38.

The spelling of 4341325512143 in words is "four trillion, three hundred forty-one billion, three hundred twenty-five million, five hundred twelve thousand, one hundred forty-three".