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43413306121 is a prime number
BaseRepresentation
bin101000011011101000…
…100111101100001001
311011001112210110020201
4220123220213230021
51202402301243441
631535505452201
73064552004413
oct503350475411
9134045713221
1043413306121
1117458752499
1284b7041061
13412b286a23
14215ba3d9b3
1511e14bbc31
hexa1ba27b09

43413306121 has 2 divisors, whose sum is σ = 43413306122. Its totient is φ = 43413306120.

The previous prime is 43413306107. The next prime is 43413306133. The reversal of 43413306121 is 12160331434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22138166521 + 21275139600 = 148789^2 + 145860^2 .

It is a cyclic number.

It is not a de Polignac number, because 43413306121 - 221 = 43411208969 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 43413306121.

It is not a weakly prime, because it can be changed into another prime (43413376121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21706653060 + 21706653061.

It is an arithmetic number, because the mean of its divisors is an integer number (21706653061).

Almost surely, 243413306121 is an apocalyptic number.

It is an amenable number.

43413306121 is a deficient number, since it is larger than the sum of its proper divisors (1).

43413306121 is an equidigital number, since it uses as much as digits as its factorization.

43413306121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 43413306121 its reverse (12160331434), we get a palindrome (55573637555).

The spelling of 43413306121 in words is "forty-three billion, four hundred thirteen million, three hundred six thousand, one hundred twenty-one".