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4341431312241 = 32034771123201
BaseRepresentation
bin111111001011010001011…
…110001001111101110001
3120101000222210221110110020
4333023101132021331301
51032112222403442431
613122232003554053
7625441500164322
oct77132136117561
916330883843406
104341431312241
111424210881a91
125a149468b929
1325651a39c6ca
141101aab92449
1577de5b2d696
hex3f2d1789f71

4341431312241 has 8 divisors (see below), whose sum is σ = 5788859657184. Its totient is φ = 2894145254400.

The previous prime is 4341431312219. The next prime is 4341431312287. The reversal of 4341431312241 is 1422131341434.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 4341431312241 - 215 = 4341431279473 is a prime.

It is a super-2 number, since 2×43414313122412 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (4341431312441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35500560 + ... + 35622641.

It is an arithmetic number, because the mean of its divisors is an integer number (723607457148).

Almost surely, 24341431312241 is an apocalyptic number.

It is an amenable number.

4341431312241 is a deficient number, since it is larger than the sum of its proper divisors (1447428344943).

4341431312241 is a wasteful number, since it uses less digits than its factorization.

4341431312241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71143551.

The product of its digits is 27648, while the sum is 33.

Adding to 4341431312241 its reverse (1422131341434), we get a palindrome (5763562653675).

The spelling of 4341431312241 in words is "four trillion, three hundred forty-one billion, four hundred thirty-one million, three hundred twelve thousand, two hundred forty-one".

Divisors: 1 3 20347 61041 71123201 213369603 1447143770747 4341431312241