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4341503000423 = 19228500157917
BaseRepresentation
bin111111001011010101101…
…111100111111101100111
3120101001011210211121011002
4333023111233213331213
51032112344232003143
613122243044303515
7625443330421631
oct77132557477547
916331153747132
104341503000423
111424248296416
125a14b46a1b9b
1325652c1ac754
141101b64d3a51
1577dec08e5b8
hex3f2d5be7f67

4341503000423 has 4 divisors (see below), whose sum is σ = 4570003158360. Its totient is φ = 4113002842488.

The previous prime is 4341503000413. The next prime is 4341503000449. The reversal of 4341503000423 is 3240003051434.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4341503000423 - 222 = 4341498806119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4341503000413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114250078940 + ... + 114250078977.

It is an arithmetic number, because the mean of its divisors is an integer number (1142500789590).

Almost surely, 24341503000423 is an apocalyptic number.

4341503000423 is a deficient number, since it is larger than the sum of its proper divisors (228500157937).

4341503000423 is a wasteful number, since it uses less digits than its factorization.

4341503000423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 228500157936.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 4341503000423 its reverse (3240003051434), we get a palindrome (7581506051857).

The spelling of 4341503000423 in words is "four trillion, three hundred forty-one billion, five hundred three million, four hundred twenty-three", and thus it is an aban number.

Divisors: 1 19 228500157917 4341503000423