Base | Representation |
---|---|
bin | 111111001011110100001… |
… | …010110011100000110111 |
3 | 120101002111101022201111111 |
4 | 333023310022303200313 |
5 | 1032114420420121403 |
6 | 13122405441015451 |
7 | 625462066205041 |
oct | 77136412634067 |
9 | 16332441281444 |
10 | 4342013442103 |
11 | 142448a434847 |
12 | 5a1617624587 |
13 | 2565b0b7c44c |
14 | 110224206a91 |
15 | 77e2bcbb56d |
hex | 3f2f42b3837 |
4342013442103 has 2 divisors, whose sum is σ = 4342013442104. Its totient is φ = 4342013442102.
The previous prime is 4342013442083. The next prime is 4342013442133. The reversal of 4342013442103 is 3012443102434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4342013442103 - 225 = 4341979887671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4342013442133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2171006721051 + 2171006721052.
It is an arithmetic number, because the mean of its divisors is an integer number (2171006721052).
Almost surely, 24342013442103 is an apocalyptic number.
4342013442103 is a deficient number, since it is larger than the sum of its proper divisors (1).
4342013442103 is an equidigital number, since it uses as much as digits as its factorization.
4342013442103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 4342013442103 its reverse (3012443102434), we get a palindrome (7354456544537).
The spelling of 4342013442103 in words is "four trillion, three hundred forty-two billion, thirteen million, four hundred forty-two thousand, one hundred three".
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