Base | Representation |
---|---|
bin | 111111001011111111111… |
… | …101001111100000000101 |
3 | 120101010000011110112121021 |
4 | 333023333331033200011 |
5 | 1032120322032311232 |
6 | 13122441223551141 |
7 | 625500020220355 |
oct | 77137775174005 |
9 | 16333004415537 |
10 | 4342211213317 |
11 | 142458103522a |
12 | 5a16718bb4b1 |
13 | 256612b36133 |
14 | 1102425a8b65 |
15 | 77e3e335397 |
hex | 3f2fff4f805 |
4342211213317 has 2 divisors, whose sum is σ = 4342211213318. Its totient is φ = 4342211213316.
The previous prime is 4342211213233. The next prime is 4342211213341. The reversal of 4342211213317 is 7133121122434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4134203159076 + 208008054241 = 2033274^2 + 456079^2 .
It is a cyclic number.
It is not a de Polignac number, because 4342211213317 - 223 = 4342202824709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4342211210317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2171105606658 + 2171105606659.
It is an arithmetic number, because the mean of its divisors is an integer number (2171105606659).
Almost surely, 24342211213317 is an apocalyptic number.
It is an amenable number.
4342211213317 is a deficient number, since it is larger than the sum of its proper divisors (1).
4342211213317 is an equidigital number, since it uses as much as digits as its factorization.
4342211213317 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 24192, while the sum is 34.
The spelling of 4342211213317 in words is "four trillion, three hundred forty-two billion, two hundred eleven million, two hundred thirteen thousand, three hundred seventeen".
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