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43423054407713 = 411059098887993
BaseRepresentation
bin10011101111110001101111…
…01110111010100000100001
312200202012111022200220200202
421313320313232322200201
521142420403412021323
6232204135323554545
712101132524324361
oct1167706756724041
9180665438626622
1043423054407713
11129216831a3962
124a5381908ba55
131b2ca12b64566
14aa19893869a1
155047eed14d28
hex277e37bba821

43423054407713 has 4 divisors (see below), whose sum is σ = 44482153295748. Its totient is φ = 42363955519680.

The previous prime is 43423054407673. The next prime is 43423054407737. The reversal of 43423054407713 is 31770445032434.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11111242222609 + 32311812185104 = 3333353^2 + 5684348^2 .

It is a cyclic number.

It is not a de Polignac number, because 43423054407713 - 210 = 43423054406689 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43423054407773) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 529549443956 + ... + 529549444037.

It is an arithmetic number, because the mean of its divisors is an integer number (11120538323937).

Almost surely, 243423054407713 is an apocalyptic number.

It is an amenable number.

43423054407713 is a deficient number, since it is larger than the sum of its proper divisors (1059098888035).

43423054407713 is a wasteful number, since it uses less digits than its factorization.

43423054407713 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1059098888034.

The product of its (nonzero) digits is 3386880, while the sum is 47.

The spelling of 43423054407713 in words is "forty-three trillion, four hundred twenty-three billion, fifty-four million, four hundred seven thousand, seven hundred thirteen".

Divisors: 1 41 1059098887993 43423054407713