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43424733132073 is a prime number
BaseRepresentation
bin10011101111110100110111…
…10010101111010100101001
312200202100211022111221121001
421313322123302233110221
521142432323140211243
6232205014052515001
712101222240255446
oct1167723362572451
9180670738457531
1043424733132073
1112922364855367
124a5400731ba61
131b2cc1c8a1b97
14aa1aa82d09cd
1550489c3b4a4d
hex277e9bcaf529

43424733132073 has 2 divisors, whose sum is σ = 43424733132074. Its totient is φ = 43424733132072.

The previous prime is 43424733132007. The next prime is 43424733132089. The reversal of 43424733132073 is 37023133742434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33830369366544 + 9594363765529 = 5816388^2 + 3097477^2 .

It is a cyclic number.

It is not a de Polignac number, because 43424733132073 - 229 = 43424196261161 is a prime.

It is a super-2 number, since 2×434247331320732 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (43424733132973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21712366566036 + 21712366566037.

It is an arithmetic number, because the mean of its divisors is an integer number (21712366566037).

Almost surely, 243424733132073 is an apocalyptic number.

It is an amenable number.

43424733132073 is a deficient number, since it is larger than the sum of its proper divisors (1).

43424733132073 is an equidigital number, since it uses as much as digits as its factorization.

43424733132073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3048192, while the sum is 46.

The spelling of 43424733132073 in words is "forty-three trillion, four hundred twenty-four billion, seven hundred thirty-three million, one hundred thirty-two thousand, seventy-three".