Base | Representation |
---|---|
bin | 10011101111110100110111… |
… | …10010101111010011100111 |
3 | 12200202100211022111221111121 |
4 | 21313322123302233103213 |
5 | 21142432323140211012 |
6 | 232205014052514411 |
7 | 12101222240255323 |
oct | 1167723362572347 |
9 | 180670738457447 |
10 | 43424733132007 |
11 | 12922364855307 |
12 | 4a5400731ba07 |
13 | 1b2cc1c8a1b46 |
14 | aa1aa82d0983 |
15 | 50489c3b4a07 |
hex | 277e9bcaf4e7 |
43424733132007 has 2 divisors, whose sum is σ = 43424733132008. Its totient is φ = 43424733132006.
The previous prime is 43424733131993. The next prime is 43424733132073. The reversal of 43424733132007 is 70023133742434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43424733132007 - 211 = 43424733129959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43424731132007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21712366566003 + 21712366566004.
It is an arithmetic number, because the mean of its divisors is an integer number (21712366566004).
Almost surely, 243424733132007 is an apocalyptic number.
43424733132007 is a deficient number, since it is larger than the sum of its proper divisors (1).
43424733132007 is an equidigital number, since it uses as much as digits as its factorization.
43424733132007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1016064, while the sum is 43.
The spelling of 43424733132007 in words is "forty-three trillion, four hundred twenty-four billion, seven hundred thirty-three million, one hundred thirty-two thousand, seven".
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