Base | Representation |
---|---|
bin | 110001010111111100111001… |
… | …1000110100010110100000111 |
3 | 2002221201201022222110210202201 |
4 | 1202233321303012202310013 |
5 | 423411034242114212411 |
6 | 4135402510510215331 |
7 | 160323112423331062 |
oct | 14257716306426407 |
9 | 2087651288423681 |
10 | 434300434132231 |
11 | 116421863973587 |
12 | 408624007b4547 |
13 | 158444805166b4 |
14 | 79363789a38d9 |
15 | 353223e7283c1 |
hex | 18afe731a2d07 |
434300434132231 has 2 divisors, whose sum is σ = 434300434132232. Its totient is φ = 434300434132230.
The previous prime is 434300434132211. The next prime is 434300434132249. The reversal of 434300434132231 is 132231434003434.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-434300434132231 is a prime.
It is a super-2 number, since 2×4343004341322312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434300434132211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217150217066115 + 217150217066116.
It is an arithmetic number, because the mean of its divisors is an integer number (217150217066116).
Almost surely, 2434300434132231 is an apocalyptic number.
434300434132231 is a deficient number, since it is larger than the sum of its proper divisors (1).
434300434132231 is an equidigital number, since it uses as much as digits as its factorization.
434300434132231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 37.
Adding to 434300434132231 its reverse (132231434003434), we get a palindrome (566531868135665).
The spelling of 434300434132231 in words is "four hundred thirty-four trillion, three hundred billion, four hundred thirty-four million, one hundred thirty-two thousand, two hundred thirty-one".
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