Base | Representation |
---|---|
bin | 1100101000111101000… |
… | …10010100011111100101 |
3 | 1112112000101121122102121 |
4 | 12110132202110133211 |
5 | 24103423311311323 |
6 | 531303322105541 |
7 | 43243313114413 |
oct | 6243642243745 |
9 | 1475011548377 |
10 | 434304010213 |
11 | 158207322a67 |
12 | 7020764b2b1 |
13 | 31c545c8038 |
14 | 1704009a2b3 |
15 | b46d2e9a5d |
hex | 651e8947e5 |
434304010213 has 2 divisors, whose sum is σ = 434304010214. Its totient is φ = 434304010212.
The previous prime is 434304010199. The next prime is 434304010229. The reversal of 434304010213 is 312010403434.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 321043492449 + 113260517764 = 566607^2 + 336542^2 .
It is a cyclic number.
It is not a de Polignac number, because 434304010213 - 213 = 434304002021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434304010513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217152005106 + 217152005107.
It is an arithmetic number, because the mean of its divisors is an integer number (217152005107).
Almost surely, 2434304010213 is an apocalyptic number.
It is an amenable number.
434304010213 is a deficient number, since it is larger than the sum of its proper divisors (1).
434304010213 is an equidigital number, since it uses as much as digits as its factorization.
434304010213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 434304010213 its reverse (312010403434), we get a palindrome (746314413647).
The spelling of 434304010213 in words is "four hundred thirty-four billion, three hundred four million, ten thousand, two hundred thirteen".
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