Base | Representation |
---|---|
bin | 101000011100110100… |
… | …001101010101101101 |
3 | 11011002221002011100001 |
4 | 220130310031111231 |
5 | 1202422334334013 |
6 | 31541454304301 |
7 | 3065212303213 |
oct | 503464152555 |
9 | 134087064301 |
10 | 43433121133 |
11 | 17468956836 |
12 | 85017b8091 |
13 | 4132403b9c |
14 | 216051acb3 |
15 | 11e30d2ddd |
hex | a1cd0d56d |
43433121133 has 16 divisors (see below), whose sum is σ = 46180886400. Its totient is φ = 40764106240.
The previous prime is 43433120971. The next prime is 43433121139. The reversal of 43433121133 is 33112133434.
43433121133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 43433121133 - 225 = 43399566701 is a prime.
It is a super-2 number, since 2×434331211332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43433121139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 187173 + ... + 349141.
It is an arithmetic number, because the mean of its divisors is an integer number (2886305400).
Almost surely, 243433121133 is an apocalyptic number.
It is an amenable number.
43433121133 is a deficient number, since it is larger than the sum of its proper divisors (2747765267).
43433121133 is a wasteful number, since it uses less digits than its factorization.
43433121133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162212.
The product of its digits is 7776, while the sum is 28.
Adding to 43433121133 its reverse (33112133434), we get a palindrome (76545254567).
The spelling of 43433121133 in words is "forty-three billion, four hundred thirty-three million, one hundred twenty-one thousand, one hundred thirty-three".
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