Base | Representation |
---|---|
bin | 101000011100110100… |
… | …010000000000001100 |
3 | 11011002221002201022011 |
4 | 220130310100000030 |
5 | 1202422340211134 |
6 | 31541454431004 |
7 | 3065212350061 |
oct | 503464200014 |
9 | 134087081264 |
10 | 43433132044 |
11 | 17468963a55 |
12 | 8501802464 |
13 | 4132408b43 |
14 | 2160520c68 |
15 | 11e30d6264 |
hex | a1cd1000c |
43433132044 has 12 divisors (see below), whose sum is σ = 77861834568. Its totient is φ = 21186893600.
The previous prime is 43433132011. The next prime is 43433132059. The reversal of 43433132044 is 44023133434.
It is a junction number, because it is equal to n+sod(n) for n = 43433131997 and 43433132015.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132417922 + ... + 132418249.
It is an arithmetic number, because the mean of its divisors is an integer number (6488486214).
Almost surely, 243433132044 is an apocalyptic number.
It is an amenable number.
43433132044 is a deficient number, since it is larger than the sum of its proper divisors (34428702524).
43433132044 is a wasteful number, since it uses less digits than its factorization.
43433132044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 264836216 (or 264836214 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 43433132044 its reverse (44023133434), we get a palindrome (87456265478).
The spelling of 43433132044 in words is "forty-three billion, four hundred thirty-three million, one hundred thirty-two thousand, forty-four".
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