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43433454341 is a prime number
BaseRepresentation
bin101000011100110101…
…011110101100000101
311011002221201002102002
4220130311132230011
51202422431014331
631541505355045
73065215161524
oct503465365405
9134087632362
1043433454341
1117469064112
128501938a85
1341324bc754
1421605a64bb
1511e314b9cb
hexa1cd5eb05

43433454341 has 2 divisors, whose sum is σ = 43433454342. Its totient is φ = 43433454340.

The previous prime is 43433454289. The next prime is 43433454347. The reversal of 43433454341 is 14345433434.

43433454341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25136834116 + 18296620225 = 158546^2 + 135265^2 .

It is a cyclic number.

It is not a de Polignac number, because 43433454341 - 210 = 43433453317 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43433454295 and 43433454304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43433454347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21716727170 + 21716727171.

It is an arithmetic number, because the mean of its divisors is an integer number (21716727171).

Almost surely, 243433454341 is an apocalyptic number.

It is an amenable number.

43433454341 is a deficient number, since it is larger than the sum of its proper divisors (1).

43433454341 is an equidigital number, since it uses as much as digits as its factorization.

43433454341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 414720, while the sum is 38.

Adding to 43433454341 its reverse (14345433434), we get a palindrome (57778887775).

The spelling of 43433454341 in words is "forty-three billion, four hundred thirty-three million, four hundred fifty-four thousand, three hundred forty-one".