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43443111221141 is a prime number
BaseRepresentation
bin10011110000010111000110…
…01101100101011110010101
312200211010021010010121022112
421320023203031211132111
521143232442433034031
6232221253443040405
712102442536404162
oct1170134315453625
9180733233117275
1043443111221141
111292a1357a7725
124a57696070105
131b3188b2418b8
14aa292d01b069
155050c5a5462b
hex2782e3365795

43443111221141 has 2 divisors, whose sum is σ = 43443111221142. Its totient is φ = 43443111221140.

The previous prime is 43443111221131. The next prime is 43443111221149. The reversal of 43443111221141 is 14112211134434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43415962068241 + 27149152900 = 6589079^2 + 164770^2 .

It is a cyclic number.

It is not a de Polignac number, because 43443111221141 - 26 = 43443111221077 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43443111221098 and 43443111221107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43443111221149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21721555610570 + 21721555610571.

It is an arithmetic number, because the mean of its divisors is an integer number (21721555610571).

Almost surely, 243443111221141 is an apocalyptic number.

It is an amenable number.

43443111221141 is a deficient number, since it is larger than the sum of its proper divisors (1).

43443111221141 is an equidigital number, since it uses as much as digits as its factorization.

43443111221141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9216, while the sum is 32.

Adding to 43443111221141 its reverse (14112211134434), we get a palindrome (57555322355575).

The spelling of 43443111221141 in words is "forty-three trillion, four hundred forty-three billion, one hundred eleven million, two hundred twenty-one thousand, one hundred forty-one".