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434472760254431 is a prime number
BaseRepresentation
bin110001011001001101001001…
…0100010100001111111011111
32002222100012010200110211200002
41202302122102202201333133
5423421400203111120211
64140014010341124515
7160341423011235443
oct14262322242417737
92088305120424602
10434472760254431
11116488954533798
124088b8943b973b
13158577b4360842
147940845548823
1535369783a503b
hex18b26928a1fdf

434472760254431 has 2 divisors, whose sum is σ = 434472760254432. Its totient is φ = 434472760254430.

The previous prime is 434472760254413. The next prime is 434472760254439. The reversal of 434472760254431 is 134452067274434.

Together with previous prime (434472760254413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 434472760254431 - 26 = 434472760254367 is a prime.

It is a super-2 number, since 2×4344727602544312 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (434472760254439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217236380127215 + 217236380127216.

It is an arithmetic number, because the mean of its divisors is an integer number (217236380127216).

Almost surely, 2434472760254431 is an apocalyptic number.

434472760254431 is a deficient number, since it is larger than the sum of its proper divisors (1).

434472760254431 is an equidigital number, since it uses as much as digits as its factorization.

434472760254431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54190080, while the sum is 56.

The spelling of 434472760254431 in words is "four hundred thirty-four trillion, four hundred seventy-two billion, seven hundred sixty million, two hundred fifty-four thousand, four hundred thirty-one".