Search a number
-
+
4345153202134 = 22172576601067
BaseRepresentation
bin111111001110101111010…
…100000010011111010110
3120101101121012100001120001
4333032233110002133112
51032142333204432014
613124045201001514
7625632642551263
oct77165724023726
916341535301501
104345153202134
111425850782a48
125a215302329a
132569914b8a14
141104411d026a
157806276a974
hex3f3af5027d6

4345153202134 has 4 divisors (see below), whose sum is σ = 6517729803204. Its totient is φ = 2172576601066.

The previous prime is 4345153202123. The next prime is 4345153202141. The reversal of 4345153202134 is 4312023515434.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 4345153202093 and 4345153202102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1086288300532 + ... + 1086288300535.

It is an arithmetic number, because the mean of its divisors is an integer number (1629432450801).

Almost surely, 24345153202134 is an apocalyptic number.

4345153202134 is a deficient number, since it is larger than the sum of its proper divisors (2172576601070).

4345153202134 is a wasteful number, since it uses less digits than its factorization.

4345153202134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2172576601069.

The product of its (nonzero) digits is 172800, while the sum is 37.

Adding to 4345153202134 its reverse (4312023515434), we get a palindrome (8657176717568).

It can be divided in two parts, 434515 and 3202134, that added together give a square (3636649 = 19072).

The spelling of 4345153202134 in words is "four trillion, three hundred forty-five billion, one hundred fifty-three million, two hundred two thousand, one hundred thirty-four".

Divisors: 1 2 2172576601067 4345153202134