4350114015413 has 4 divisors (see below), whose sum is σ = 4350342039840. Its totient is φ = 4349885990988.

The previous prime is 4350114015409. The next prime is 4350114015421. The reversal of 4350114015413 is 3145104110534.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4350114015413 - 2² = 4350114015409 is a prime.

It is a super-2 number, since 2×4350114015413² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4350114015413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4350114015433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113983595 + ... + 114021752.

It is an arithmetic number, because the mean of its divisors is an integer number (1087585509960).

Almost surely, 2^{4350114015413} is an apocalyptic number.

It is an amenable number.

4350114015413 is a deficient number, since it is larger than the sum of its proper divisors (228024427).

4350114015413 is a wasteful number, since it uses less digits than its factorization.

4350114015413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 228024426.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 4350114015413 its reverse (3145104110534), we get a palindrome (7495218125947).

The spelling of 4350114015413 in words is "four trillion, three hundred fifty billion, one hundred fourteen million, fifteen thousand, four hundred thirteen".