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4350114433121 is a prime number
BaseRepresentation
bin111111010011010111000…
…001101000100001100001
3120101212101221202201000212
4333103113001220201201
51032233013243324441
613130225345223505
7626166614405462
oct77232701504141
916355357681025
104350114433121
111427967210246
125a30b8631b95
132572a22c2162
1411079207cd69
15782530b4eeb
hex3f4d7068861

4350114433121 has 2 divisors, whose sum is σ = 4350114433122. Its totient is φ = 4350114433120.

The previous prime is 4350114433111. The next prime is 4350114433153. The reversal of 4350114433121 is 1213344110534.

It is an a-pointer prime, because the next prime (4350114433153) can be obtained adding 4350114433121 to its sum of digits (32).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3179035510225 + 1171078922896 = 1782985^2 + 1082164^2 .

It is a cyclic number.

It is not a de Polignac number, because 4350114433121 - 238 = 4075236526177 is a prime.

It is not a weakly prime, because it can be changed into another prime (4350114433111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175057216560 + 2175057216561.

It is an arithmetic number, because the mean of its divisors is an integer number (2175057216561).

Almost surely, 24350114433121 is an apocalyptic number.

It is an amenable number.

4350114433121 is a deficient number, since it is larger than the sum of its proper divisors (1).

4350114433121 is an equidigital number, since it uses as much as digits as its factorization.

4350114433121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 4350114433121 its reverse (1213344110534), we get a palindrome (5563458543655).

The spelling of 4350114433121 in words is "four trillion, three hundred fifty billion, one hundred fourteen million, four hundred thirty-three thousand, one hundred twenty-one".