Base | Representation |
---|---|
bin | 111111010011010111000… |
… | …001101000100001100001 |
3 | 120101212101221202201000212 |
4 | 333103113001220201201 |
5 | 1032233013243324441 |
6 | 13130225345223505 |
7 | 626166614405462 |
oct | 77232701504141 |
9 | 16355357681025 |
10 | 4350114433121 |
11 | 1427967210246 |
12 | 5a30b8631b95 |
13 | 2572a22c2162 |
14 | 11079207cd69 |
15 | 782530b4eeb |
hex | 3f4d7068861 |
4350114433121 has 2 divisors, whose sum is σ = 4350114433122. Its totient is φ = 4350114433120.
The previous prime is 4350114433111. The next prime is 4350114433153. The reversal of 4350114433121 is 1213344110534.
It is an a-pointer prime, because the next prime (4350114433153) can be obtained adding 4350114433121 to its sum of digits (32).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3179035510225 + 1171078922896 = 1782985^2 + 1082164^2 .
It is a cyclic number.
It is not a de Polignac number, because 4350114433121 - 238 = 4075236526177 is a prime.
It is not a weakly prime, because it can be changed into another prime (4350114433111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175057216560 + 2175057216561.
It is an arithmetic number, because the mean of its divisors is an integer number (2175057216561).
Almost surely, 24350114433121 is an apocalyptic number.
It is an amenable number.
4350114433121 is a deficient number, since it is larger than the sum of its proper divisors (1).
4350114433121 is an equidigital number, since it uses as much as digits as its factorization.
4350114433121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 4350114433121 its reverse (1213344110534), we get a palindrome (5563458543655).
The spelling of 4350114433121 in words is "four trillion, three hundred fifty billion, one hundred fourteen million, four hundred thirty-three thousand, one hundred twenty-one".
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