Base | Representation |
---|---|
bin | 111111010011100010110… |
… | …111100010100110110111 |
3 | 120101212220210121202000101 |
4 | 333103202313202212313 |
5 | 1032233420124122124 |
6 | 13130301203454531 |
7 | 626204546230234 |
oct | 77234267424667 |
9 | 16355823552011 |
10 | 4350313114039 |
11 | 1427a59382152 |
12 | 5a3153087447 |
13 | 257304506c29 |
14 | 1107b05da78b |
15 | 7826575d644 |
hex | 3f4e2de29b7 |
4350313114039 has 2 divisors, whose sum is σ = 4350313114040. Its totient is φ = 4350313114038.
The previous prime is 4350313114031. The next prime is 4350313114087. The reversal of 4350313114039 is 9304113130534.
4350313114039 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4350313114039 - 23 = 4350313114031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4350313113989 and 4350313114007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4350313114031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175156557019 + 2175156557020.
It is an arithmetic number, because the mean of its divisors is an integer number (2175156557020).
Almost surely, 24350313114039 is an apocalyptic number.
4350313114039 is a deficient number, since it is larger than the sum of its proper divisors (1).
4350313114039 is an equidigital number, since it uses as much as digits as its factorization.
4350313114039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 37.
The spelling of 4350313114039 in words is "four trillion, three hundred fifty billion, three hundred thirteen million, one hundred fourteen thousand, thirty-nine".
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