Base | Representation |
---|---|
bin | 111111010100010100001… |
… | …010000000111000111101 |
3 | 120101222001102121221112012 |
4 | 333110110022000320331 |
5 | 1032242113322242003 |
6 | 13130515223421005 |
7 | 626234210050646 |
oct | 77242412007075 |
9 | 16358042557465 |
10 | 4351140040253 |
11 | 1428343134046 |
12 | 5a3343bb4765 |
13 | 257406926996 |
14 | 11084c3746cd |
15 | 782b31538d8 |
hex | 3f514280e3d |
4351140040253 has 2 divisors, whose sum is σ = 4351140040254. Its totient is φ = 4351140040252.
The previous prime is 4351140040243. The next prime is 4351140040307. The reversal of 4351140040253 is 3520400411534.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4123933378009 + 227206662244 = 2030747^2 + 476662^2 .
It is a cyclic number.
It is not a de Polignac number, because 4351140040253 - 214 = 4351140023869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4351140040213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175570020126 + 2175570020127.
It is an arithmetic number, because the mean of its divisors is an integer number (2175570020127).
Almost surely, 24351140040253 is an apocalyptic number.
It is an amenable number.
4351140040253 is a deficient number, since it is larger than the sum of its proper divisors (1).
4351140040253 is an equidigital number, since it uses as much as digits as its factorization.
4351140040253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 4351140040253 its reverse (3520400411534), we get a palindrome (7871540451787).
The spelling of 4351140040253 in words is "four trillion, three hundred fifty-one billion, one hundred forty million, forty thousand, two hundred fifty-three".
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