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43512412043 = 215320210131
BaseRepresentation
bin101000100001100010…
…101011011110001011
311011022110021120000102
4220201202223132023
51203103134141133
631553410000015
73100164254102
oct504142533613
9134273246012
1043512412043
11174a9693211
12852427600b
134145976599
14216ac7b039
1511ea0467e8
hexa218ab78b

43512412043 has 4 divisors (see below), whose sum is σ = 43532624328. Its totient is φ = 43492199760.

The previous prime is 43512412001. The next prime is 43512412049. The reversal of 43512412043 is 34021421534.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 43512412043 - 26 = 43512411979 is a prime.

It is a super-2 number, since 2×435124120432 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43512411997 and 43512412015.

It is not an unprimeable number, because it can be changed into a prime (43512412049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10102913 + ... + 10107218.

It is an arithmetic number, because the mean of its divisors is an integer number (10883156082).

Almost surely, 243512412043 is an apocalyptic number.

43512412043 is a deficient number, since it is larger than the sum of its proper divisors (20212285).

43512412043 is a wasteful number, since it uses less digits than its factorization.

43512412043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20212284.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 43512412043 its reverse (34021421534), we get a palindrome (77533833577).

The spelling of 43512412043 in words is "forty-three billion, five hundred twelve million, four hundred twelve thousand, forty-three".

Divisors: 1 2153 20210131 43512412043