4351342501141 has 2 divisors, whose sum is σ = 4351342501142. Its totient is φ = 4351342501140.

The previous prime is 4351342501117. The next prime is 4351342501249. The reversal of 4351342501141 is 1411052431534.

4351342501141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4005662002225 + 345680498916 = 2001415^2 + 587946^2 .

It is a cyclic number.

It is not a de Polignac number, because 4351342501141 - 2²⁹ = 4350805630229 is a prime.

It is a super-3 number, since 3×4351342501141³ (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4351342501097 and 4351342501106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4351342501111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175671250570 + 2175671250571.

It is an arithmetic number, because the mean of its divisors is an integer number (2175671250571).

Almost surely, 2^{4351342501141} is an apocalyptic number.

It is an amenable number.

4351342501141 is a deficient number, since it is larger than the sum of its proper divisors (1).

4351342501141 is an equidigital number, since it uses as much as digits as its factorization.

4351342501141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 4351342501141 its reverse (1411052431534), we get a palindrome (5762394932675).

The spelling of 4351342501141 in words is "four trillion, three hundred fifty-one billion, three hundred forty-two million, five hundred one thousand, one hundred forty-one".