4353153124345 has 4 divisors (see below), whose sum is σ = 5223783749220. Its totient is φ = 3482522499472.

The previous prime is 4353153124301. The next prime is 4353153124387. The reversal of 4353153124345 is 5434213513534.

4353153124345 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 553710109689 + 3799443014656 = 744117^2 + 1949216^2 .

It is a cyclic number.

It is not a de Polignac number, because 4353153124345 - 2¹⁵ = 4353153091577 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435315312430 + ... + 435315312439.

It is an arithmetic number, because the mean of its divisors is an integer number (1305945937305).

Almost surely, 2^{4353153124345} is an apocalyptic number.

It is an amenable number.

4353153124345 is a deficient number, since it is larger than the sum of its proper divisors (870630624875).

4353153124345 is an equidigital number, since it uses as much as digits as its factorization.

4353153124345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 870630624874.

The product of its digits is 1296000, while the sum is 43.

Adding to 4353153124345 its reverse (5434213513534), we get a palindrome (9787366637879).

The spelling of 4353153124345 in words is "four trillion, three hundred fifty-three billion, one hundred fifty-three million, one hundred twenty-four thousand, three hundred forty-five".