Base | Representation |
---|---|
bin | 111111010110010001100… |
… | …100011100100000010111 |
3 | 120102011111001211022211212 |
4 | 333112101210130200113 |
5 | 1032310420443333421 |
6 | 13131504105252035 |
7 | 626340306332324 |
oct | 77262144344027 |
9 | 16364431738755 |
10 | 4353244121111 |
11 | 14292228aa146 |
12 | 5a383079401b |
13 | 257680813142 |
14 | 1109ab9a3b4b |
15 | 78387c24e5b |
hex | 3f59191c817 |
4353244121111 has 4 divisors (see below), whose sum is σ = 4353251942424. Its totient is φ = 4353236299800.
The previous prime is 4353244121089. The next prime is 4353244121113. The reversal of 4353244121111 is 1111214423534.
4353244121111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4353244121111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4353244121113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3006020 + ... + 4212201.
It is an arithmetic number, because the mean of its divisors is an integer number (1088312985606).
Almost surely, 24353244121111 is an apocalyptic number.
4353244121111 is a deficient number, since it is larger than the sum of its proper divisors (7821313).
4353244121111 is an equidigital number, since it uses as much as digits as its factorization.
4353244121111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7821312.
The product of its digits is 11520, while the sum is 32.
Adding to 4353244121111 its reverse (1111214423534), we get a palindrome (5464458544645).
The spelling of 4353244121111 in words is "four trillion, three hundred fifty-three billion, two hundred forty-four million, one hundred twenty-one thousand, one hundred eleven".
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