Base | Representation |
---|---|
bin | 10011110011001011110000… |
… | …01100111000001101010001 |
3 | 12201011101121102212020021112 |
4 | 21321211320030320031101 |
5 | 21201330111112341200 |
6 | 232334013523503105 |
7 | 12112445161430255 |
oct | 1171457014701521 |
9 | 181141542766245 |
10 | 43540100121425 |
11 | 12967286480a66 |
12 | 4a72443527a95 |
13 | 1b3aa76c8181b |
14 | aa74d01c6265 |
15 | 5078a0756535 |
hex | 279978338351 |
43540100121425 has 12 divisors (see below), whose sum is σ = 54003402946416. Its totient is φ = 34823255067600.
The previous prime is 43540100121337. The next prime is 43540100121457. The reversal of 43540100121425 is 52412100104534.
It is not a de Polignac number, because 43540100121425 - 212 = 43540100117329 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 43540100121391 and 43540100121400.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 220525091 + ... + 220722440.
It is an arithmetic number, because the mean of its divisors is an integer number (4500283578868).
Almost surely, 243540100121425 is an apocalyptic number.
It is an amenable number.
43540100121425 is a deficient number, since it is larger than the sum of its proper divisors (10463302824991).
43540100121425 is a wasteful number, since it uses less digits than its factorization.
43540100121425 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 441251488 (or 441251483 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 43540100121425 its reverse (52412100104534), we get a palindrome (95952200225959).
The spelling of 43540100121425 in words is "forty-three trillion, five hundred forty billion, one hundred million, one hundred twenty-one thousand, four hundred twenty-five".
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