Base | Representation |
---|---|
bin | 111111010111010011000… |
… | …010100001000011101101 |
3 | 120102021022121122221010122 |
4 | 333113103002201003231 |
5 | 1032320143141214432 |
6 | 13132205104014325 |
7 | 626406444521456 |
oct | 77272302410355 |
9 | 16367277587118 |
10 | 4354342523117 |
11 | 14297369228a4 |
12 | 5a3a986013a5 |
13 | 2577c7254662 |
14 | 110a7380812d |
15 | 783ee392612 |
hex | 3f5d30a10ed |
4354342523117 has 2 divisors, whose sum is σ = 4354342523118. Its totient is φ = 4354342523116.
The previous prime is 4354342523107. The next prime is 4354342523137. The reversal of 4354342523117 is 7113252434534.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2526084281956 + 1828258241161 = 1589366^2 + 1352131^2 .
It is a cyclic number.
It is not a de Polignac number, because 4354342523117 - 228 = 4354074087661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4354342523107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2177171261558 + 2177171261559.
It is an arithmetic number, because the mean of its divisors is an integer number (2177171261559).
Almost surely, 24354342523117 is an apocalyptic number.
It is an amenable number.
4354342523117 is a deficient number, since it is larger than the sum of its proper divisors (1).
4354342523117 is an equidigital number, since it uses as much as digits as its factorization.
4354342523117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1209600, while the sum is 44.
The spelling of 4354342523117 in words is "four trillion, three hundred fifty-four billion, three hundred forty-two million, five hundred twenty-three thousand, one hundred seventeen".
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