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435483285552001 is a prime number
BaseRepresentation
bin110001100000100011101101…
…0100010100111101110000001
32010002220210110221002210002001
41203001013122202213232001
5424034424232100131001
64142110132021224001
7160504425532445311
oct14301073242475601
92102823427083061
10435483285552001
11116838473739515
1240a136b3262001
13158cbb890b83bb
1479777097b3441
153552dbdb8d001
hex18c11da8a7b81

435483285552001 has 2 divisors, whose sum is σ = 435483285552002. Its totient is φ = 435483285552000.

The previous prime is 435483285551999. The next prime is 435483285552043. The reversal of 435483285552001 is 100255582384534.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 433871236339776 + 1612049212225 = 20829576^2 + 1269665^2 .

It is a cyclic number.

It is not a de Polignac number, because 435483285552001 - 21 = 435483285551999 is a prime.

It is a super-2 number, since 2×4354832855520012 (a number of 30 digits) contains 22 as substring.

Together with 435483285551999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (435483285552061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217741642776000 + 217741642776001.

It is an arithmetic number, because the mean of its divisors is an integer number (217741642776001).

Almost surely, 2435483285552001 is an apocalyptic number.

It is an amenable number.

435483285552001 is a deficient number, since it is larger than the sum of its proper divisors (1).

435483285552001 is an equidigital number, since it uses as much as digits as its factorization.

435483285552001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040000, while the sum is 55.

The spelling of 435483285552001 in words is "four hundred thirty-five trillion, four hundred eighty-three billion, two hundred eighty-five million, five hundred fifty-two thousand, one".