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43554314113 = 23282333297
BaseRepresentation
bin101000100100000010…
…100001011110000001
311011102101010101211221
4220210002201132001
51203144401022423
632001504035041
73101213363422
oct504402413601
9134371111757
1043554314113
1117520302922
128536302a81
134151557acb
142172667649
1511eda71e5d
hexa240a1781

43554314113 has 6 divisors (see below), whose sum is σ = 45530313794. Its totient is φ = 41660647776.

The previous prime is 43554314101. The next prime is 43554314119. The reversal of 43554314113 is 31141345534.

It can be written as a sum of positive squares in only one way, i.e., 37290699664 + 6263614449 = 193108^2 + 79143^2 .

It is not a de Polignac number, because 43554314113 - 25 = 43554314081 is a prime.

It is a super-3 number, since 3×435543141133 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43554314119) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 41166120 + ... + 41167177.

Almost surely, 243554314113 is an apocalyptic number.

It is an amenable number.

43554314113 is a deficient number, since it is larger than the sum of its proper divisors (1975999681).

43554314113 is an equidigital number, since it uses as much as digits as its factorization.

43554314113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82333343 (or 82333320 counting only the distinct ones).

The product of its digits is 43200, while the sum is 34.

Adding to 43554314113 its reverse (31141345534), we get a palindrome (74695659647).

The spelling of 43554314113 in words is "forty-three billion, five hundred fifty-four million, three hundred fourteen thousand, one hundred thirteen".

Divisors: 1 23 529 82333297 1893665831 43554314113