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43572056137 is a prime number
BaseRepresentation
bin101000100101000110…
…001101000001001001
311011110121111210022221
4220211012031001021
51203213421244022
632003340214041
73101520236431
oct504506150111
9134417453287
1043572056137
111752a320755
12854023a321
13415512a54c
142174b652c1
1512003c8cc7
hexa2518d049

43572056137 has 2 divisors, whose sum is σ = 43572056138. Its totient is φ = 43572056136.

The previous prime is 43572056131. The next prime is 43572056149. The reversal of 43572056137 is 73165027534.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28749237136 + 14822819001 = 169556^2 + 121749^2 .

It is a cyclic number.

It is not a de Polignac number, because 43572056137 - 223 = 43563667529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43572056093 and 43572056102.

It is not a weakly prime, because it can be changed into another prime (43572056131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21786028068 + 21786028069.

It is an arithmetic number, because the mean of its divisors is an integer number (21786028069).

Almost surely, 243572056137 is an apocalyptic number.

It is an amenable number.

43572056137 is a deficient number, since it is larger than the sum of its proper divisors (1).

43572056137 is an equidigital number, since it uses as much as digits as its factorization.

43572056137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 529200, while the sum is 43.

The spelling of 43572056137 in words is "forty-three billion, five hundred seventy-two million, fifty-six thousand, one hundred thirty-seven".