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43633122133121 is a prime number
BaseRepresentation
bin10011110101111001000001…
…01111101100010010000001
312201111021201022012001002222
421322330200233230102001
521204341113231224441
6232444440220220425
712122250304454453
oct1172744057542201
9181437638161088
1043633122133121
11129a2780a27184
124a8848439a715
131b4677cbc42b1
14aabbd65ba2d3
15509ee7073d4b
hex27af20bec481

43633122133121 has 2 divisors, whose sum is σ = 43633122133122. Its totient is φ = 43633122133120.

The previous prime is 43633122133109. The next prime is 43633122133123. The reversal of 43633122133121 is 12133122133634.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26853538561600 + 16779583571521 = 5182040^2 + 4096289^2 .

It is a cyclic number.

It is not a de Polignac number, because 43633122133121 - 218 = 43633121870977 is a prime.

Together with 43633122133123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (43633122133123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21816561066560 + 21816561066561.

It is an arithmetic number, because the mean of its divisors is an integer number (21816561066561).

Almost surely, 243633122133121 is an apocalyptic number.

It is an amenable number.

43633122133121 is a deficient number, since it is larger than the sum of its proper divisors (1).

43633122133121 is an equidigital number, since it uses as much as digits as its factorization.

43633122133121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 46656, while the sum is 35.

Adding to 43633122133121 its reverse (12133122133634), we get a palindrome (55766244266755).

The spelling of 43633122133121 in words is "forty-three trillion, six hundred thirty-three billion, one hundred twenty-two million, one hundred thirty-three thousand, one hundred twenty-one".