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4371982943 is a prime number
BaseRepresentation
bin1000001001001011…
…10010101001011111
3102021200122202010012
410010211302221133
532423211423233
62001454433435
7213225145646
oct40445625137
912250582105
104371982943
111943963549
12a2020287b
13548a03773
142d690435d
151a8c52548
hex104972a5f

4371982943 has 2 divisors, whose sum is σ = 4371982944. Its totient is φ = 4371982942.

The previous prime is 4371982931. The next prime is 4371982981. The reversal of 4371982943 is 3492891734.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4371982943 - 230 = 3298241119 is a prime.

It is a super-2 number, since 2×43719829432 = 38228469707765882498, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4371982891 and 4371982900.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4371982843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2185991471 + 2185991472.

It is an arithmetic number, because the mean of its divisors is an integer number (2185991472).

Almost surely, 24371982943 is an apocalyptic number.

4371982943 is a deficient number, since it is larger than the sum of its proper divisors (1).

4371982943 is an equidigital number, since it uses as much as digits as its factorization.

4371982943 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1306368, while the sum is 50.

The square root of 4371982943 is about 66120.9720361097. The cubic root of 4371982943 is about 1635.1571069810.

The spelling of 4371982943 in words is "four billion, three hundred seventy-one million, nine hundred eighty-two thousand, nine hundred forty-three".