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43954311075061 is a prime number
BaseRepresentation
bin10011111111001111010010…
…00110010001010011110101
312202121222202111211211211111
421333213221012101103311
521230121412113400221
6233252155354035021
712154410542435062
oct1177475106212365
9182558674754744
1043954311075061
1113006a11796142
124b1a781a18a71
131b6ab4881c96a
14abd585895c69
15513544a52be1
hex27f9e91914f5

43954311075061 has 2 divisors, whose sum is σ = 43954311075062. Its totient is φ = 43954311075060.

The previous prime is 43954311075053. The next prime is 43954311075071. The reversal of 43954311075061 is 16057011345934.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42920186822500 + 1034124252561 = 6551350^2 + 1016919^2 .

It is a cyclic number.

It is not a de Polignac number, because 43954311075061 - 23 = 43954311075053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43954311074996 and 43954311075014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43954311075001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21977155537530 + 21977155537531.

It is an arithmetic number, because the mean of its divisors is an integer number (21977155537531).

Almost surely, 243954311075061 is an apocalyptic number.

It is an amenable number.

43954311075061 is a deficient number, since it is larger than the sum of its proper divisors (1).

43954311075061 is an equidigital number, since it uses as much as digits as its factorization.

43954311075061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1360800, while the sum is 49.

The spelling of 43954311075061 in words is "forty-three trillion, nine hundred fifty-four billion, three hundred eleven million, seventy-five thousand, sixty-one".