Base | Representation |
---|---|
bin | 111111111111110000000… |
… | …000001110011110011101 |
3 | 120120102102201102122001111 |
4 | 333333300000032132131 |
5 | 1034023122200304231 |
6 | 13204151131542021 |
7 | 632505020240332 |
oct | 77776000163635 |
9 | 16512381378044 |
10 | 4397778134941 |
11 | 14460a611a954 |
12 | 5b039abba911 |
13 | 25b92a01b109 |
14 | 112bd43b2989 |
15 | 795e27b84b1 |
hex | 3fff000e79d |
4397778134941 has 2 divisors, whose sum is σ = 4397778134942. Its totient is φ = 4397778134940.
The previous prime is 4397778134927. The next prime is 4397778134947. The reversal of 4397778134941 is 1494318777934.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2366166915225 + 2031611219716 = 1538235^2 + 1425346^2 .
It is a cyclic number.
It is not a de Polignac number, because 4397778134941 - 25 = 4397778134909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4397778134947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2198889067470 + 2198889067471.
It is an arithmetic number, because the mean of its divisors is an integer number (2198889067471).
Almost surely, 24397778134941 is an apocalyptic number.
It is an amenable number.
4397778134941 is a deficient number, since it is larger than the sum of its proper divisors (1).
4397778134941 is an equidigital number, since it uses as much as digits as its factorization.
4397778134941 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 128024064, while the sum is 67.
The spelling of 4397778134941 in words is "four trillion, three hundred ninety-seven billion, seven hundred seventy-eight million, one hundred thirty-four thousand, nine hundred forty-one".
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