Base | Representation |
---|---|
bin | 1000001100011100… |
… | …00100101100000101 |
3 | 102100121002121020212 |
4 | 10012032010230011 |
5 | 33002211213223 |
6 | 2004312405205 |
7 | 214006413200 |
oct | 40616045405 |
9 | 12317077225 |
10 | 4399319813 |
11 | 19583350a9 |
12 | a293a6805 |
13 | 551585525 |
14 | 2da3bc937 |
15 | 1ab352278 |
hex | 106384b05 |
4399319813 has 12 divisors (see below), whose sum is σ = 5119133292. Its totient is φ = 3769698240.
The previous prime is 4399319783. The next prime is 4399319839. The reversal of 4399319813 is 3189139934.
4399319813 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 3733576609 + 665743204 = 61103^2 + 25802^2 .
It is not a de Polignac number, because 4399319813 - 212 = 4399315717 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4399319843) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 175481 + ... + 198977.
It is an arithmetic number, because the mean of its divisors is an integer number (426594441).
Almost surely, 24399319813 is an apocalyptic number.
It is an amenable number.
4399319813 is a deficient number, since it is larger than the sum of its proper divisors (719813479).
4399319813 is a wasteful number, since it uses less digits than its factorization.
4399319813 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27332 (or 27325 counting only the distinct ones).
The product of its digits is 629856, while the sum is 50.
The square root of 4399319813 is about 66327.3685065223. The cubic root of 4399319813 is about 1638.5580987170.
The spelling of 4399319813 in words is "four billion, three hundred ninety-nine million, three hundred nineteen thousand, eight hundred thirteen".
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