Base | Representation |
---|---|
bin | 10100000000011101111110… |
… | …01110101110000101100011 |
3 | 12202210000210210111020210221 |
4 | 22000032333032232011203 |
5 | 21231314422412214341 |
6 | 233323423451103511 |
7 | 12160434505206235 |
oct | 1200167716560543 |
9 | 182700723436727 |
10 | 43996558319971 |
11 | 13022921202584 |
12 | 4b269b2441b97 |
13 | 1b71b1c335c2a |
14 | ac16326bc255 |
15 | 5146b8989ed1 |
hex | 2803bf3ae163 |
43996558319971 has 2 divisors, whose sum is σ = 43996558319972. Its totient is φ = 43996558319970.
The previous prime is 43996558319953. The next prime is 43996558320037. The reversal of 43996558319971 is 17991385569934.
43996558319971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43996558319971 - 217 = 43996558188899 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43996558319891 and 43996558319900.
It is not a weakly prime, because it can be changed into another prime (43996558319911) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21998279159985 + 21998279159986.
It is an arithmetic number, because the mean of its divisors is an integer number (21998279159986).
Almost surely, 243996558319971 is an apocalyptic number.
43996558319971 is a deficient number, since it is larger than the sum of its proper divisors (1).
43996558319971 is an equidigital number, since it uses as much as digits as its factorization.
43996558319971 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1984046400, while the sum is 79.
The spelling of 43996558319971 in words is "forty-three trillion, nine hundred ninety-six billion, five hundred fifty-eight million, three hundred nineteen thousand, nine hundred seventy-one".
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