Base | Representation |
---|---|
bin | 1100110011100100011… |
… | …00001001011110001101 |
3 | 1120001201112020110002201 |
4 | 12121302030021132031 |
5 | 24202111111420331 |
6 | 534045003321501 |
7 | 43534446061405 |
oct | 6316214113615 |
9 | 1501645213081 |
10 | 440002451341 |
11 | 15a670a05142 |
12 | 71337b20291 |
13 | 3265206b5ab |
14 | 17420c0b805 |
15 | b6a3716a61 |
hex | 667230978d |
440002451341 has 2 divisors, whose sum is σ = 440002451342. Its totient is φ = 440002451340.
The previous prime is 440002451297. The next prime is 440002451347. The reversal of 440002451341 is 143154200044.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 394567397316 + 45435054025 = 628146^2 + 213155^2 .
It is a cyclic number.
It is not a de Polignac number, because 440002451341 - 225 = 439968896909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (440002451347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220001225670 + 220001225671.
It is an arithmetic number, because the mean of its divisors is an integer number (220001225671).
Almost surely, 2440002451341 is an apocalyptic number.
It is an amenable number.
440002451341 is a deficient number, since it is larger than the sum of its proper divisors (1).
440002451341 is an equidigital number, since it uses as much as digits as its factorization.
440002451341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 440002451341 its reverse (143154200044), we get a palindrome (583156651385).
The spelling of 440002451341 in words is "four hundred forty billion, two million, four hundred fifty-one thousand, three hundred forty-one".
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